The expression in (A5) is strictly negative if the expression in
the bracket is negative. The expression in the bracket is the derivative
of [gamma](x) = x [e.sup.*'](x)[mu]'([e.sup.*](x)) with
respect to x = [s.sub.i] [DELTA][w.sup.*.sub.i]. Using the first-order
conditions for optimal effort, we obtain that [gamma](x) =
[e.sup.*]'(x)[psi]'([e.sup.*](x)). Thus, using (A1),
[gamma]'(x) = [e.sup.*]" [psi]'([e.sup.*]) +
[([e.sup.*]').sup.2] [psi]"([e.sup.*]) =
[([e.sup.*]').sup.2][psi]'([e.sup.*])[[e.sup.*]'[x[mu'"([e.sup.*]) -
[psi]'"([e.sup.*])]/[mu]'([e.sup.*]) +
2[mu]"([e.sup.*])/[mu]'([e.sup.*]) +
[psi]"([e.sup.*])/[psi]'([e.sup.*])], which is negative by
Assumptions 1, 2, and 3. Hence, the partial derivatives in (A4) and (A5)
have the same sign, so that [DELTA][w.sup.*]' ([s.sub.i]) < 0.
Proposition 1 (iii), combined with the fact that [DELTA][w.sup.*] (s) is
strictly decreasing in s, implies that all agents with zero low
performance wage and for whom (IR) is not binding must have identical
status levels.
Finally, suppose that there are two agents i and j with =
[[w.bar].sub.j] = 0 and such that (IR) is binding for i only. Then, from
Proposition 1(iii), this can only be possible if [s.sub.i] <
[s.sub.j]. We have shown above that [[partial
derivative].sup.2][PI]/[partial derivative][w.sup.*.sub.i] < 0 so
that profit is concave in [DELTA][w.sup.*]. Hence, because the (IR)
constraint for j is not binding, we must have [DELTA][w.sup.j] =
[DELTA][w.sup.*]([s.sub.j]), which is optimal if the (IR) constraint is
ignored. Similarly, the (IR) constraint being binding for i implies that
[DELTA][w.sup.i] > [DELTA][w.sup.*i]([s.sub.i]) so that
[DELTA][w.sup.*]([s.sub.i]) < [DELTA][w.sup.*]([s.sub.j]), which
contradicts our result above that [DELTA][w.sup.*] is decreasing in
status. Thus, this situation cannot be part of any optimal solution.
Proof of Proposition 3. Consider a steady state. There then exists
([c.sub.1], [c.sub.l], [c.sub.h]) such that ([c.sub.1t], [c.sub.lt],
[c.sub.ht]) = ([c.sub.1], [c.sub.l], [c.sub.h]) for all t. The proof
proceeds in three steps.
Step 1. [c.sub.1] = (0, 0, 0). If [s.sub.1] = 0, then it is optimal
to set [[w.bar].sub.1] = [DELTA][[w.bar].sub.1] = 0. Thus, the proof of
the result amounts to showing that [s.sub.1] = 0. Suppose to the
contrary that [s.sub.1] > 0. At some date t, the principal may switch
to
[MATHEMATICAL EXPRESSION NOT REPRODUCIBLE IN ASCII]. (A6)
If each generation from t on is offered these contracts, the
young's expected intertemporal utility is held constant. Basically,
the young's wages are transferred from the first to the second
period while being divided by the ratio of the original period 1 status
to the new second period status [s.sub.1]/[s.sub.1]+[s.sub.p], p [member
of] {l, h}, so that the increase in status exactly compensates for the
decrease in income. The new intertemporal utility is
[MATHEMATICAL EXPRESSION NOT REPRODUCIBLE IN ASCII], (A7)
which is the intertemporal utility in the original contract. On the
other hand, the utility of an old agent is increased (by
[s.sub.1][[w.bar].sub.1]/[delta] for the l type and
[s.sub.1]([[w.bar].sub.1] + [DELTA][w.sub.1])/[delta] for the h type).
Furthermore, all effort levels are maintained. Finally, the
intertemporal wage bill for each generation is lower: that is,
([mu]([e.sub.1])[s.sub.1]/[s.sub.h] + [s.sub.1] + (1 - [mu])
([w.sub.1))[s.sub.1])/[s.sub.l]+[s.sub.1])E[w.sub.1] +
[delta][mu]([e.sub.1]) [s.sub.h]/[s.sub.h]+[s.sub.1] E[w.sub.h] +
[delta](1 - [mu]([e.sub.1])) [s.sub.l]/ [s.sub.l]+[s.sub.1] E[w.sub.l]
< E[w.sub.1] + [delta][mu]([e.sub.1])E[w.sub.h] + [delta](1 -
[mu]([e.sub.1]))E[w.sub.l]. Hence, a steady state with [s.sub.1] > 0
cannot be part of any optimal solution.
Step 2. If [U.sub.h] > [U.sub.l], then ([s.sub.h] >
[s.sub.l]) and ([[w.bar].sub.h] [greater than or equal to]
[[w.bar].sub.l] and ([DELTA][w.sub.h] > [DELTA][w.sub.l]) must hold.
First note that the arguments used to prove Proposition 1(iii) may be
applied to the old population at each period so that ([s.sub.h] >
[s.sub.l]) implies ([[w.bar].sub.h] [greater than or equal to]
[[w.bar].sub.l]) and ([DELTA][[w.sub.h] [greater than or equal to]
[DELTA][w.sub.l]). Furthermore, if [U.sub.h] > [U.sub.l], we cannot
have [s.sub.l] > [s.sub.h], because this would imply that wages for
type l old workers should be at least as high as those of type h old
workers, which contradicts [U.sub.h] > [U.sub.l].
Step 3. [U.sub.h] > [U.sub.l]. Because young agents have no
status, proving the result amounts to showing that a steady state in
which the young's effort is zero cannot be part of an optimal
solution. In such a steady state, at each date, only the old exert
effort. Now suppose that at some date t, the principal commits to giving
only half of the status to the old at date t + 1. Then she is in a
position to implement the egalitarian solution of Proposition 2, which
is optimal in the static problem. That is, all agents can be awarded
identical status and wages and they all exert the same effort: in
particular, young agents are not induced to exert additional effort by
the prospect of future utility differentials because there are none.
Because the solution in which only the old (i.e., one fraction of the
agents) exert effort is also feasible in the static problem, this yields
a strictly lower per-period profit than the egalitarian solution. Thus,
the young's effort must be strictly positive in the steady state of
an optimal solution. Because the young exert effort in spite of zero
status, we must have [U.sub.h] > [U.sub.l].
Proof of Proposition 4. Consider a steady state. An agent may face
four possible states of nature depending on her performance in each of
the two periods (i.e., ll, lh, hi, hh). To simplify the notation, the
reference to the state of nature is dropped in the remainder of the
proof. For one such state of nature, let st and w t denote the
agent's status and wage when young, and [s.sub.2] and [w.sub.2] the
agent's status and wage when old. Let v = g([s.sub.i])h([w.sub.i])
+ [delta]g ([s.sub.2])h([w.sub.2]). Now suppose that [s.sub.l] > 0.
If the principal switches to a solution ([s'.sub.1],
[w'.sub.1], [s'.sub.2], [w'.sub.2]), with [s'.sub.1]
= [w'.sub.1] = 0 and [s'.sub.2] = [s.sub.1] + [s.sub.2], v is
unchanged as long as
h([w'.sub.2]) = g([s.sub.1])h([w.sub.1]) +
[delta]g([s.sub.2])h([w.sub.2])/[delta]g([s.sub.1] + [s.sub.2]) (A8)
It can easily be shown that if this is done for all states of
nature, effort levels and intertemporal expected utility are unchanged
whereas the agent's utility when old increases. Suppose that h(w) =
w. Then (A8) becomes to [w'.sub.2] = g([s.sub.1])h([w.sub.1]) +
[delta]g([s.sub.2])h([w.sub.2]) /[delta]g([s.sub.1] + [s.sub.2]) Because
g is strictly increasing, the discounted wage bill
[delta][w'.sub.2] is lower than [w.sub.1~] + [delta] [w.sub.2].
Thus, the principal is better off. Suppose that g(s) is linear. Then
(A8) can be written as
h([w'.sub.2]) = 1/[delta] [s.sub.1]/[s.sub.1] + [s.sub.2]
h([w.sub.1]) + [s.sub.2]/ [s.sub.1]/[s.sub.1] + [s.sub.2] h([w.sub.2]).
(A9)
Strict monotonicity and concavity of h imply
h([w.sub.1] + [w.sub.2]) > h[s.sub.1][w.sub.1] +
[s.sub.2][w.sub.2]/[s.sub.1] + [s.sub.2] [greater than or equal to]
[s.sub.1]h([w.sub.1]) + [s.sub.2]h([w.sub.2])/([s.sub.1] + [s.sub.2]).
(A10)
Thus, for [delta] close to 1, because h is strictly increasing, if
[w'.sub.2] satisfies (A9), then [delta][w'.sub.2] <
[w.sub.1] + [delta][w.sub.2].
We would like to thank the editor and an anonymous referee for
their fruitful comments and suggestions. We are also indebted to seminar
participants at Fourgeot seminar (Pads), Institut d'Analisi
Economica (Barcelona), Universit6 d'Aix-Marseille 2, Universit6
Catholique de Louvain, Universit6 de Caen, Universite des Sciences
Sociales de Toulouse, University of Virginia, Stockholm School of
Economics, Erasmus University, and the participants in the workshop
Social Interaction and Economic Behavior in Paris December 1999 for
stimulating criticism and comments on an early version of the article,
participants at the conference Organizational Behaviour, Structure and
Change; The Economics of Personnel and Organizations in Toulouse May
2003, and especially Lucy White, for their comments and fruitful
discussions. We are thankful to Thomas Madotti and Made-Christine
Henninger for their help and suggestions. Finally, we are also grateful
to Andrew Clark for proofreading the entire manuscript and improving the
English. All remaining errors are ours.
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